Closing line simplified to one line (status + result path); tree removed
Co-Authored-By: Claude <noreply@anthropic.com>
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@ -630,15 +630,10 @@ def _cmd_eval_run(args) -> int:
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mark = '[green]✓[/green]' if ok_n == len(rows) else '[yellow]◐[/yellow]'
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mark = '[green]✓[/green]' if ok_n == len(rows) else '[yellow]◐[/yellow]'
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if console is not None:
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if console is not None:
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console.print(
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console.print(
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f'\n{mark} [bold]运行结束[/bold] · {ok_n}/{len(rows)} benchmarks ok\n'
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f'\n{mark} [bold]运行结束[/bold] · {ok_n}/{len(rows)} benchmarks ok'
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f' 结果 {ap}\n'
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f' · 结果 {ap}')
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f' ├─ summary.xlsx (excel 打开总表)\n'
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f' ├─ summary.csv\n'
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f' └─ <bench>/report.jsonl + detail.md (每 benchmark 一个目录)')
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else:
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else:
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print(f'\n运行结束 · {ok_n}/{len(rows)} benchmarks ok\n'
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print(f'\n运行结束 · {ok_n}/{len(rows)} benchmarks ok · 结果 {ap}')
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f' 结果 {ap}\n'
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f' ├─ summary.xlsx\n └─ <bench>/report.jsonl + detail.md')
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elif rows and rows[0]['ok'] and args.out:
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elif rows and rows[0]['ok'] and args.out:
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_notice('运行结束 · 结果已保存', args.out)
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_notice('运行结束 · 结果已保存', args.out)
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print(f'{ok_n}/{len(rows)} benchmarks ok')
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print(f'{ok_n}/{len(rows)} benchmarks ok')
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